C++ program to find the sum of digits, reverse & prime or not of a number

Aim: To write a program to find the reverse and sum of digits of a number. Also, check whether it is prime or not.

Algorithm:

Step 1: Start.

Step 2: Declare a class number.

Step 3: Define and declare the function getdata() to read the number.

Step 4: Define and declare the function prime() to print whether the number is prime or not.

Step 5: Define and declare the function putdata() to print the sum of digits and reverse of the number.

Step 6: Create an object for the class number.

Step 7: Call the functions getdata(), prime(), and putdata() for the object.

Step 8: Stop.

Program Code:

#include<iostream.h>
#include<conio.h>
class number{
int n,d,s,r,i,f;
public:  
void getdata();  
void prime();
void putdata();
};
void number::getdata()
{
cout<<"Enter the number : ";
cin>>n;
}
void number::prime()
{
f=0;
for(i=2;i<=n/2;i++)
{
if(n%i==0)
{
f=1;
break;
}
}
if(f==1)
cout<<"\nNumber is not prime\n";
else
 cout<<"\nNumber is prime\n"; }
void number::putdata()
{
s=0;
r=0;
while(n>0)
{
d=n%10;
s=s+d;
r=r*10+d;
n=n/10;
}
cout<<"\nSum of digit = "<<s;
cout<<"\nReverse of the number = "<<r;
}
void main()
{
number obj;
clrscr();
obj.getdata();
obj.prime();
obj.putdata();
getch();
}

Output:

Enter the number : 736

Number is not prime

Sum of digits = 16

Reverse of the number = 637